Find the perimeter of the following shape, rounded to the nearest tenth: 22.8
19.1
12.4
6.9

P = 18.4 units

Step-by-step explanation:

Sides AB and CD are congruent and thus have the same length.

Sides AD and BC are congruent.

The length of side AB is found using the Pythagorean Theorem:

|AB| = √ [ 5² + 1² ] = √26

and

|BC| = √ [ 4² + 1² ] = √17

Then the perimeter is P = 2(√26) + 2(√17), or

                                           10.20    +  8.25, or, to the nearest tenth,

                                      P = 18.4 units              

19.1 units

Step-by-step explanation:

Sides CB and DA your length are equals

Sides AB and DC your length are equals

Using the Pythagoras Theorem:

c² = a² + b²

Side AB:

c² = 1² + 5²

c² = 1 + 25

c² = 26

√c² = √26

c = 5.1     aprox.

Side CB:

c² = 2² + 4²

c² = 4 + 16

c² = 20

√c² = √20

c = 4.472     aprox

then:

the perimeter:

p = AB + BC + CD + DA

AB = CD = 5.1

DA = BC = 4.472

p = 2(5.1 + 4.472)

p = 2(9.572)

p = 19.144    aprox.

then the correct optión is:

19.1 units

step-by-step explanation:

cats

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .