An automotive plant makes the Quartz and the Pacer. The plant has a maximum production capacity of 1200 cars per week, and they can make at most 600 Quartz cars and 800 Pacers each week. If the profit on a Quartz is $500 and the profit on a Pacer is $800, find how many of each type of car the plant should produce.

x=400 and y=800

Step-by-step explanation:

let x be the Quartez and y is Pacer

x+y≤1200 ( maximum production capacity of 1200 cars per week)

0≤x≤600

0≤y≤800

profit : 500x+800y

at a point : x=0 y=800

profit=500x+800y ⇒ 500(0)+800(800)=640000

profit= 500(600)+0=300000 wen x=600(max), y=0

Profit=500(600)+800(600)= 780000

profit =500(400)+800(800)=840000 this is the max profit when

x=400 and y=800

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x