Answer using ac-method. 6x^2-2x=20

2(3x+5)(x-2)=0 is the factorized form

Step-by-step explanation:

6x²-2x=20

6x²-2x-20=0

taking 2 as common

2(3x²-x-10)=0

by using sum and product rule

2(3x²-6x+5x-10)=0

2[3x(x-2)+5(x-2)]=0

2[(3x+5)(x-2)]=0

2(3x+5)(x-2)=0

hope it will help :)

answer;

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