Struggling on this one may i please get some help

diameter 12.81 units to the hundredths

Step-by-step explanation:

Assuming O is the intersection of extensions of PS and QR, at the circumference of T.

PT is chord and TS is perpendicular to PT passing through the centre T. Therefore PS is a perpendicular bisector.

SO = 10/2 = 5

Similarly, RO = 5

Consider right triangle ORT right-angled at R

radius = OT = sqrt(OR^2+RT^2) = sqrt(5^2+4^2) = sqrt(41)

Therefore diameter = 2sqrt(41)   = 12.806 (to the third decimal place)

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204