Our school's girls volleyball team has 14 players, including a set of 3 triplets: Alicia, Amanda, and Anna. In how many ways can we choose 6 starters if exactly two of the triplets are in the starting lineup?

990 ways to choose 6 starters out of 14 with exactly two of the three triplets.

Step-by-step explanation:

Ways to choose 2 of the triplets

= C(3,2) = 3! / (2!1!) = 3

Ways to choose the remaining 4 starters out of 11 players left

= C(11,4) = 11! / (4!7!) = 330

Total number of ways to choose 6 starters

= 3*330 = 990

i believe the answer is the polygon, heptagon.