How would you verify the trigonometric identity 2x = 2sinx cosx

Step-by-step explanation:

Hi, there!!

I hope you mean sin2x=2sinx . cosx

so, let's begin in a simple way; by adding, alright:

sin2x= sin(x+x)(as 2x=x+x).

now, let's use compound formula for sin,

so, we get:

sin (x+x)= sinx.cosx + cosx. sinx (as sin(A+B)=sin A. cosB + cosA . sinB)

or, sin (x+x)=2sinx.cosx (adding both).

Therefore, sin 2x = 2sinx. cosx.

Hope it helps..

Step-by-step explanation:

2x = 2sinx cosx is not an identity.  An identity is "always true," whereas a conditional equation is true only for specific value(s) of the unknown.  Double check to ensure that you have copied down this problem correctly.

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1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: