By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made. If the cardboard is 16 in. long and 6 in. wide, find the dimensions (in inches) of the box that will yield the maximum volume. (Round your answers to two decimal places if necessary.)

x=3.00 or x= 8.00

Explanation:

Let us denote side of the cut-out square as x inches

Then base of box = 16-2x by 6-2x

The volume = V = (16-2x)(6-2x)

= 96-3x-12x+4x

dV/dx = 96-44x+4x^2

= 0 for a max V

divide by 4

X^2 -11x +24=0

Using quadratic formula to solve the equation

X= (11± √11^2-(4×1×24)/2

(11± √25)/2

x= 3 or 8inches

From the equation of volume = V = x(16-2x)(6-2x)

Substitute

let x = 3 , V = 3(16-6)(6-6) = 0

let x = 8 , V = 8(16-16)(6-16) = 0

Therefore, the maximum volume exist at both point x=3 or x= 8

the system of inequity is

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

the solid line passing through the points (0,4) and (4,0).

the related equation of solid line is .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

the related equation of dashed line is

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be . the required inequality is

similarly, check the second related equation.

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

i can you with this sweetie!

step-by-step explanation: