of the digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select a DVR that is not defective? The probability is nothing.

Full question:

Eighteen of 50 digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select an item that is not defective?

16/25

Step-by-step explanation:

Probability is the likelihood of an event happening and it is calculated as the number of favourable outcomes divided by the total number of possible outcomes. From the above we can calculate probability of finding a DVR that is not defective by adding up number of DVRS that are not defective in the DVRS(favourable outcomes) and dividing it by the total number of DVRS(total number of possible outcomes).

Non defective dvrs=total number of dvrs-defective dvrs=50-18=32

So probability here=non defective dvrs/total number of dvrs

=32/50=16/25

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.