There are two consecutive integers such that the larger is nine more than twice the smaller. What is the larger number?

Step-by-step explanation:

Let the consecutive numbers be x and x+1 (Since they are coming one after another)

So, Given Condition is:

x+1 = 9 + 2(x)

x+1 = 9 +2x

Subtracting -2x to both sides

x+1-2x = 9

-x+1 = 9

Subtracting 1 from both sides

-x = 9-1

-x = 8

=> x = -8

The larger number is:

=> x+1 = -8+1 = -7

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204