Jacque needs to buy some pizzas for a party at her office. She's ordering from a restaurant that charges a $7.50 delivery fee and $14 per pizza. She wants to buy as many pizzas as she can, and she also needs to
keep the delivery fee plus the cost of the pizzas under $60.
Each pizza is cut into 8 slices, and she wonders how many total slices she can afford.
Let P represent the number of pizzas that Jacque buys.
1) Which inequality describes this scenario?
Choose 1
7.50 +14P < 60
B
7.50+ 14P > 60
14 + 7.50P < 60
D
14+ 7.50P > 60

A.    7.50 +14P < 60

Step-by-step explanation:

Let P represent the number of pizzas that Jacque buys.

Given, delivery fee =$7.50

Per pizza cost = $14

She wants to buy as many pizzas as she can, and she also needs to

keep the delivery fee plus the cost of the pizzas under $60.

i.e.  (delivery fee) + (Number of pizzas) x (Per pizza cost) < $60

i.e. 7.50 +14P<60

Required inequality :  7.50 +14P<60

A.    7.50 +14P < 60   Jacque can only afford 24 slices of pizza

Step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100