Mathematics, 31.07.2020 05:01 martinezalex829
Which of the graphs above is the graph of the equation below? Y=x^3-6x^2+11x-6=(x-3)(x-2)(x-1)
Answers: 3
Mathematics, 21.06.2019 16:00, bryce12351
An equation of the line tangent to y=x^3+3x^2+2 at its point of inflection is
Answers: 3
Mathematics, 21.06.2019 16:10, dhernandez081
To find the extreme values of a function f(x. y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x, y)=xy
Answers: 2
Which of the graphs above is the graph of the equation below? Y=x^3-6x^2+11x-6=(x-3)(x-2)(x-1)
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