In the given graph of a cubic polynomial, what are the number of real zeros and complex zeros, respectively?

1 real and 2 complex.

Step-by-step explanation:

A cubic polynomial is written as:

a*x^3 + b*x^2 + c*x + d

And the zeros are such that:

a*x^3 + b*x^2 + c*x + d  = 0

As the degree of the polynomial is 3, then we have 3 solutions (where some of them may be equal)

Now, an easy way to see the real and complex zeros of a polynomial is:

If after a change in curvature, the line touches the x-axis : that is a real zero

if it does not, then there we have a complex zero.

Here we can see two lines that do not touch the x-axis and one line that does touch the x-axis.

Then we have 2 complex zeros and one real zero.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.