Find the focus. y= -1/12 (x)² - 6

Step-by-step explanation:

Hello,

We know that when the parabola equation is

the vertex is (h,k) and the focus is

Here, the equation is

so

So,

Then, the focus is

I attached the graph, included the focus so that you can see it :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)