Set of six numbers has an average of 42. When three of this numbers were removed the remaining three numbers had an average of 72. What was the sum of the removed numbers?

36

Step-by-step explanation:

From the question, we are informed that six numbers has an average of 42. This means that the total number will be equal to:

= 42 × 6

= 252

When three of this numbers were removed the remaining three numbers had an average of 72. The total of this will be:

= 72 × 3

= 216

The sum of the removed numbers will be the difference between the two numbers above. This will be:

= 252 - 216

= 36

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong