Please help I am not sure how to solve this problem.

Measure of arc TSU = 201°

Step-by-step explanation:

For the inscribed circle of  triangle XYZ, we have;

∠XZY = 21°

Segment TZ and segment  UZ are tangent to circle R

Therefore, ∠ZUR = ∠ZTR = 90° (angle formed by a tangent)

Length UR = Length TR = Radius of circle R

∴ ΔZTR ≅ ΔZUR Side Angle Side (SAS) rule of Congruency

∴ ∠RZT ≅ ∠RZU, (Congruent Parts of Congruent Triangles are Congruent, CPCTC)

∠XZY = ∠RZT + ∠RZU (Angle summation)

21° = ∠RZT + ∠RZU  = 2×∠RZU (Transitive property)

∠RZU = 21°/2 = 10.5° = ∠RZT

∴ ∠URZ = 180- 90 - 10.5 = 79.5° = ∠TRZ (CPCTC)

arc TU = ∠URT = ∠URZ + ∠TRZ = 79.5 + 79.5 = 159° (angle addition)

∴ Measure of arc TSU = 360° - 159° = 201° (Sum of angles at the center of the circle R)

Measure of arc TSU = 201°.

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: