The initial population of a town is , and it grows with a doubling time of 10 years. What will the population be in years?

This question is incomplete, i will answer it as:

"The initial population of a town is A, and it grows with a doubling time of 10 years. What will the population be in X years?"

Ok, the growth of a population usually is an exponential growth, so we can write this as:

P(t) = A*exp(r*t)

Where A is the initial population.

r is the rate of growth, and t is our variable, in this case, number of years.

Now we know that when t = 10y, the population doubles, so we should have:

P(10y) = 2*A = A*exp(r*10y)

2 = exp(r*10)

ln(2) = r*10

ln(2)/10 = r = 0.069.

Then our equation is:

P(t) = A*exp(0.069*t)

Now, if we want to know the population in X years, we need to replace the variable t by X

P(t = X) = A*exp(0.069*X)

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

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step-by-step explanation: