a square has an area of 36 and one side that lies along the line y=3. what could be the location of one of the vertices of this shape? a) (9, 4) b) (-5, -3) c) (6, 5) d) (3, 6)

Correct answer is:

b) (-5, -3)

Step-by-step explanation:

Given that area of square is 36 and one sides lies along the line y = 3

To find:

Possible location of a vertex can be = ? Answer to be chosen from the options:

a) (9, 4)

b) (-5, -3)

c) (6, 5)

d) (3, 6)

Solution:

First of all, let us try to find the side of square.

Now, given that one side lies on the line y = 3 that means 2 of its coordinates will have their y - coordinates as 3.

Now, we know that all the angles of a square are .

So, coordinates of adjacent vertices will have a change in only x value or either y value.

Therefore, we can say that The other two coordinates of the square will have the y coordinates the value either 3 + 6 = 9 or 3 -6 = -3

One such possible square is attached in the answer area.

possible location of the one of the vertex is:

b) (-5, -3)

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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