A party mix is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $1 per kg. How much of each should be added to obtain 60 kg of a mix that will sell for $1.40 per kg?

1. The amount of nuts is kg and cereal mixture is kg to obtain 60 kg of a mix that will sell for $1.40 per kg.

n=16 kg

c=44 kg

Step-by-step explanation:

Let

n=nuts at $2.50 per kg

c=cereal at $1 per kg

n+c=60 (1)

2.5n + c=1.40(60) (2)

From (1)

n=60-c

Substitute n=60-c into (2)

2.5n + c=1.40(60)

2.5(60-c) +c=84

150-2.5c+c=84

-1.5c=84-150

-1.5c= -66

Divide both sides by -1.5

c=44 kg

Substitute c=44 into (1)

n+c=60

n+44=60

n=60-44

=16

n=16 kg

The amount of nuts is 16 kg and cereal mixture is 44 kg to obtain 60 kg of a mix that will sell for $1.40 per kg.

where is the shape my dude?

step-by-step explanation:

robert puts 2 in each row