11. Which of the following lines is perpendicular to the line 3x-9y = 17? A) 12x + y = 4
B) 9x - 3y = 11
C) 6x + 2y = 8
D) 3x - y = 5

Step-by-step explanation:

When using the equation of a line, one calculates the value of

y

in terms of

x

, say

y

=

m

x

+

c

, then

m

is the slope of the line and

c

is its intercept on

y

-axis.

As

3

x

−

9

y

=

15

can be written as

3

x

−

15

=

9

y

or

y

=

3

9

x

−

15

9

or

y

=

1

3

x

−

5

3

Hence slope of

3

x

−

9

y

=

15

is

1

3

Product of slopes of two perpendicular lines is

−

1

Hence, the slope of the line that is perpendicular to the line

3

x

−

9

y

=

15

is

−

1

1

3

=

−

1

×

3

1

=

−

3

graph{(3x-9y-15)(3x+y+5)=0 [-10, 10, -7.04, 2.96]}

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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