Two quadratic functions are shown: which function has lowest minimum value, and what are it's coordinates?

function 1 has the lowest minimum value and it's coordinates are (-1,4)

function 1 has the lowest minimum value and it's coordinates are (0,7)

function 2 has the lowest minimum value and it's coordinates are (-1,7)

function 2 has the lowest minimum value and it's coordinates are (0,3)

To find the minimum value of function 1, we need to find the vertex. The formula for the x-coordinate of the vertex is -b/2a, which is -1 in this equation. However, to find minimum and maximum values, we need to look at the y-coordinate. f(-1) is 4, which we know is a minimum (rather than a maximum), because the leading coefficient is positive -- so the parabola opens upwards. So, the minimum value of f(x) is 4, and the coordinate is (-1, 4).

From the table, the minimum value of g(x) is 3, and the coordinate is (0, 3).

Therefore, function 2 has the lowest minimum value, with coordinates (0, 3).

is there any attachment? what are the equations?

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!