What constant acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 3 seconds? (Round your answer to two decimal places.) ft/s2

 12.22 ft/sec²

Step-by-step explanation:

An increase from 26 to 51 is an increase of 51 - 26 = 25 mi/hr

We need to do this in 3 seconds -->   25 mi/hr ÷ 3 sec

Note the following conversion: 1 mile = 5280 ft

step-by-step explanation:

i have no idea

hey there!

12 is twice as much as 6 because 6 goes into 12 2 times.

since the rabbit is twice as tall, we should multiply the weight of the first rabbit, 0.25, by 2.

0.25 x 2 = 0.5

therefore, the 12 inch chocolate rabbit weighs 0.5 lb, or half a pound.

hope this !