n ant needs to travel along a 20cm × 20cm cube to get from point A to point B. What is the shortest path he can take, and how long will it be (in cm)?

Step-by-step explanation:

Since the shape is a cube of side 20cm, then all the side of the cube will be 20cm since all the side of a cube are all equal.

The shortest path the ant can be take is to first travel along the diagonal of the square from point A to the other edge on the front face and then move to point B on its adjacent side on a straight line.

To get the total distance he will take, we will first calcuate the value of the diagonal distance of the square face using pythagoras theorem as shown.

hypotenuse² = opposite² + adjacent²

The opposite = adjacent = 20cm

The hypotenuse is the length of the diagonal that we need.

hyp² = 20²+20²

hyp² = 400+400

hyp² = 800

hyp = √800

hyp = 28.28 cm

The length of the diagonal is 28.28 cm.

Afterwards, the ant will move 20cm to point B from the stopping point.

Total distance will be 28.28 + 20 = 48.28 cm

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: