If θ is an angle in standard position that terminates in Quadrant IV such that cosθ = 3/5 then cosθ/2 = - (√5)/5
- (2√2)/5
- (2√5)/5
- (4√5)/5

300pi

step-by-step explanation:

ratio is 2 : 9

the answer is three

13.5 : 3

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry