A window is composed of a semicircle placed on top of a rectangle. If you have 26 ft of window framing materials for the outer frame, what are the dimensions that maximizes the area (in ft2) of the window you can create? (Round your answers to two decimal places.) radius of semicircle ft
width of rectangle ft
height of rectangle ft

there is no image or shapes attacted

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

ok then what happened.

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?