Consider the following 8 numbers, where one labelled x is unknown. 4, 32, 6, x , 10, 3, 35, 37 Given that the range of the numbers is 64, work out 2 values of x

The needed two values of x are: 67 and -27.

Given sequence of 8 numbers as:

Given range of above sequence: 64

The range of a sequence is defined as the difference between the maximum and minimum value of the sequence.

Since the value x can assume any value, it have option to be minimum value in the sequence or maximum value in the sequence such that  the range remains at 64.

Case 1: x as minimum value of given sequence:

If so, then the maximum value is 37. Then-

Case 2: x as maximum value of the given sequence:

If so, then the minimum value of the sequence is 3. Then-

Thus the needed two values of x are: 67 and -27.

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Step-by-step explanation:

There can be two values of x.

The range is largest no. - smallest no.

Range = 64

Let x be the smallest no.

largest no. from the list is 37

37 - x = 64

-x = 64 - 37

x = -27

Let x be the largest no.

smallest no. from the list is 3

x - 3 = 64

x = 64 + 3

x = 67

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: