Raise -2 to the double of b and divide the result by the quadruple of a. A=-4 and B =+3.

- 4

Step-by-step explanation:

Given that A = - 4, B = 3

According to the instruction :

Raise -2 to the double of b and divide the result by the quadruple of a. A=-4 and B =+3

Raise - 2 to the double of b ;

Result = (-2)^(2*3) = (-2)^6 = 64

Divide result by quadruple of a

a = - 4 ;

Quadruple of 'a' means 4 times as many as 'a' = '4 * a' quadruple of a = (-4) * 4 = - 16

= (-2)^6 / -16

64 / - 16

64 / - 16 = - 4

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.