HELP SOMEONE What is the equation of the line that is perpendicular to
the given line and has an x-intercept of 6?
10
-8-
6
10
-10 -8 -6 22
|(4,2)
O y=-x+8
O ý= 3x + 6
Oy -x-8
o y=-x-16
-6-
10-

Explanation:

Original line goes through (-4,4) and (4,-2)

Slope formula

m = (y2 - y1)/(x2 - x1)

m = (-2 - 4)/(4 - (-4))

m = (-2 - 4)/(4 + 4)

m = -6/8

m = -3/4

Flip the fraction and the sign to go from -3/4 to 4/3.

The perpendicular slope is 4/3. The perpendicular line goes through (x1,y1) = (6,0) which is the x intercept

y - y1 = m(x - x1)

y - 0 = (4/3)(x - 6)

y = (4/3)(x - 6)

y = (4/3)x - (4/3)(6)

y = (4/3)x - 8

You were close, but the -6 at the end should be -8 instead.

It's possible you were thinking of the y intercept since the -6 is similar to the 6 from the x intercept.