Calculate how much 30% alcohol solution and 80% alcohol solution must be mixed to end up with exactly 14 gallons of a 40% alcohol solution. You'll need gallons of the 80% solution.

You'll need 2.8 gallons of the 80% solution.

Step-by-step explanation:

Let the volume of 30% alcohol =x gallons

Then the volume of 80% alcohol =(14-x) gallons

Since we want to obtain a 40% alcohol solution, we have:

0.3x+0.8(14-x)=0.4(14)

0.3x+11.2-0.8x=5.6

0.8x-0.3x=11.2-5.6

0.5x=5.6

x=11.2

Therefore, the volume of 80% alcohol

=14-11.2

=2.8 gallons

You'll need 2.8 gallons of the 80% solution.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .