Please help immediately

The require gradient is 3/5

Step-by-step explanation:

y(x) = 5x/(2x^2+4)(1)

y(sqrt(3)) = sqrt(3)/2 => (sqrt(3), sqrt(3)/2) is a point on the curve of (1)

differentiate y(x) with respect to x using the quotient rule to get

y'(x) = 20x^2/(2x^2+4)^2 (2)

substitute x = (sqrt(3), sqrt(3)/2) in (2)

y'(sqrt(3))

= 20(sqrt(3))^2 / (2(sqrt(3))^2 + 4)^2

= 20*3 / (10)^2

= 60 / 100

= 3/5

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.