Chelsey puts twelve colored pieces of chocolate candy in a bag. Three pieces are green, four pieces are yellow, two pieces are purple, and three pieces are red. She draws one piece of candy from the bag at a time and eats it. A. What is the probability that Chelsey will draw out three pieces of candy in this order: red, green, yellow?
B. What is the probability that Chelsey will draw out three pieces of candy in this order: green, yellow, red?
C. What is the probability that Chelsey will draw out three pieces of candy in this order: yellow, red, green? D. Make a conclusion about how the order in which she draws out the red, green, and yellow pieces affects the probability.

A) 3/110

B) 3/110

C) 3/110

D) The order doesn’t matter as long as you are drawing out the same three colors.  The probability doesn’t change.

Step-by-step explanation:

A) 3/12x3/11x4/10=36/1320= 9/330 = 3/110

B) 3/12x4/11x3/10=36/1320= 9/330 = 3/110

C) 4/12x3/11x3/10=36/1320 = 9/330 = 3/110

D) The order doesn’t matter as long as you are drawing out the same three colors.  The probability doesn’t change.

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: