How many solutions does the following system of equations have? y=5/2x+2
2y=5x+4
A. One
B. Zero
C. Two
D. Infinitely many

D. Infinitely many

Step-by-step explanation:

Divide 2 from both sides in 2y=5x+4

You get Y=5/2x+2

This equation is the same as the first one, meaning X could be anything. Therefore there are infinitely many solutions.

B) Zero

Step-by-step explanation:

The system of equations is:

y = 5x/2 + 2 (1)

2y = 5x + 4 (2)

Let's solve the equations:

Put (1) in (2):

2(5x/2) + 2) = 5x + 4

5x + 4 = 5x + 4

5x - 5x = 4 - 4

This will yield 0 = 0

Therefore, this system of equations has 0 solutions.

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.