Draw a vector representing the course of a ship that goes 50 miles on a course with direction 2400.

The answer is below

Step-by-step explanation:

We have a vector with a magnitude of 50 miles and a direction of 240 °.

To draw it, the first thing is to make a Cartesian plane, the first thing is to know in which quadrant it would be, 240 ° is in the third quadrant (180 ° - 270 °), that is, it would be 30 ° (270 ° - 240 °) with respect to to the y axis negative.

Knowing this angle, we calculate the value of x and y, knowing that the magnitude of the vector is 50 miles, that is, this value would be the hypotenuse.

The value on the x-axis can be calculated using the sine of the angle, like this:

sin 30 ° = x / 50

x = sin 30 ° * 50

x = 25, how is the third quadrant would be -25

Now to calculate the value on the y-axis it would be by means of Pythagoras and it would be:

y ^ 2 = 50 ^ 2 - 25 ^ 2

y ^ 2 = 1875

y = 43.3, -43.3 because it must be located in the fourth quadrant

Which means that to draw the vector that we are asked to do, we must draw a point from origin (0,0) to (-25, -43.3).

Then I leave a sketch of what it would be:

the function makes a strait line horizontally with no x intercept but a y intercept at 9.