What is the solution to the system that is created by the equation y = 2 x + 10 and the graph shown below? On a coordinate plane, a line goes through (negative 2, 0) and (0, 2). (–8, –6) (–4, –2) (0, 2) (2, 4)

  (–8, –6)

Step-by-step explanation:

The given points represent the x- and y- intercepts of the line, so we can write the equation in intercept form as ...

  x/(x-intercept) +y/(y-intercept) = 1

  x/(-2) +y/2 = 1 . . . use the given intercepts

  x - y = -2 . . . . . multiply by -2

Then the system is ...

Using the first to substitute into the second, we get ...

  x - (2x +10) = -2

  -8 = x . . . . . . . . . . . add x+2, simplify

  y = 2(-8) +10 = -6

The solution is (x, y) = (-8, -6).

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)