Write a linear equation in point-slope form for the line that goes through (-1,1) and (1,-5).
A. y+1 = -3(x+1)
B. y-1 = 3(x+1)
C. y+ 1 = 2(x - 1)
D. y-1=-3(x + 1)

y -1 = -3(x+1)

Step-by-step explanation:

First find the slope

(-1,1) and (1,-5)

m = (y2-y1)/(x2-x1)

   = (-5-1)/(1--1)

   =-6/ (1+1)

   = -6/2

   = -3

We are using point slope form

y-y1 = m(x-x1)  where m is the slope

y - 1 = -3( x - -1)

y -1 = -3(x+1)

The answer is option D.

Step-by-step explanation:

Equation of a line is y= mx + c

where m is the slope

Slope of the line using points

(-1,1) and (1,-5) is

Therefore the equation of the line using point (-1,1) is

Hope this helps you

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse