Use this scenario for questions 16-20: A city council begins hosting music nights in the park. They want to understand the success of the program, so they record attendance on 4 different nights (n = 4). On average, the city saw an average attendance of 47 (s = 4.7). Other cities that have launched a similar program and have seen an average attendance of μ = 53 (σ = 4.2). Is the city attendance different from other cities that have launched these music programs (alpha = .05)? What would be the hypotheses for this test? (HINT: remember one-tailed and two-tailed tests!).

Step-by-step explanation:

To identify the null hypothesis, the null hypothesis is the default statement while the alternative hypothesis is the opposite of the null and always tested against the null hypothesis.

The alternative hypothesis depending on the case study can give rise to a one-tailed or a two-tailed test. The one tailed test includes either less than or greater than option and not both while the two tailed test involves both.

In this case study,

the null hypothesis is u1 (representing the city in particular) = u2 (representing other cities)

The alternative hypothesis is u1 (representing the city in particular) =/ u2 (representing other cities).

This, this test due to its not equal to sign is a two tailed test, the two results might differ maybe with one higher than the other, or lower than the other.

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24