A body is projected at an angle of 30degrees to the horizontal with a speed of 30m/s. What will be the angle with the horizontal after 1.5sec. Take g as 10m/s^2

Given Information:

Launch angle of projectile = 30°

Initial velocity = V₀ = 30 m/s

Acceleration due to gravity = g = 10 m/s²

Required Information:

Angle with the horizontal after 1.5 sec = ?

The angle of the projectile to the horizontal after t = 1.5 seconds is 0°

Step-by-step explanation:

The horizontal component of the velocity is given by

Where V₀ is the initial velocity and θ is the launch angle

The vertical component of the velocity is given by

Where V₀ is the initial velocity, θ is the launch angle, g is the acceleration due to gravity and t is the time.

So after t = 1.5 sec

The horizontal component of the velocity is

And the vertical component of the velocity is

The angel is

Therefore, the angle of the projectile to the horizontal after t = 1.5 seconds is 0°

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i