Find the largest of three consecutive whole numbers such that twice the sum of the two smallest numbers is 13 more than three times the largest number.

17, 18, 19

Step-by-step explanation:

Let's say that the three consecutive numbers are

x-1,x,x+1.

Twice the sum of the two smallest numbers:

2(x -1 +x)

13 more than three times the largest number

13+3(x+1).

2(2x-1)=13+3x+3

4x-2=3x+16

4x-3x=16+2

x=18. So the numbers are:

17, 18, 19

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3