Simplify: |3r−15| if r<5

if

Step-by-step explanation:

Given that:

r < 5

To simplify:

|3r−15|

Solution:

First of all, let us learn about Modulus function:

In other words, we can say:

Modulus function has a role to make its contents positive.

If the contents are positive, the result will be equal to its contents only.

If the contents are negative, it will add a negative sign to the contents to make it positive.

Now, let us consider the given condition:

Multiply both sides with 3. (As 3 is a positive number, the equality sign will not change.)

Subtracting 15 from both sides:

Now, we know that , let us use the definition of Modulus function.

Add a negative sign to the contents because the contents are already negative.

So, the answer is:

if

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )