Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 3x(1/3) + 6x(4/3). You must justify your answer using an analysis of f ′(x) and f ′′(x).

We have an extrema (local minimum) at x = -0.125

An inflection point at x = 0.25

Step-by-step explanation:

The given function is given as follows;

At the extrema points, f'(x) = 0 which gives;

(8x + 1) =x- (0/((x)^(1/0.3)) = 0

x = -1/8 = -0.125

f''(x)  gives;

Substituting x = -0.125 gives f''(x) = 32 which is a minimum point

The inflection point is given as follows;

x = 2/3×3/8 = 1/4 = 0.25

We check the value of f''(x) at x = 0.24 and 0.26 to determine if x = 0.25 is an inflection point as follows;

At x = 0.24,   f''(x) = -0.288

At x = 0.26,   f''(x) = 0.252

0.25 is an inflection point

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step-by-step explanation:

in english this is

ex.15 pag.85 create. write in ten lines the continuation of the ballad of the five motanasi, using verbs to the imperfect and to the perfect compound. five stars

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