According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1 comma 200 Americans results in 132 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

Even is not unusual.

Step-by-step explanation:

Given:

P = 0.10

n = 1200

x = 132

1. Sample of proportion ( ˆp ) = x/n

= 132/1200

= 0.11

2. Z = ˆp - p / √p ( 1 - p )/ n

= 0.11 - 0.10 / √0.10 ( 1 - 0.10 ) / 132

= 0.01 / 0.02611

= 0.3829

3. Probability

P ( ≥ 132 ) = P( Z > 1.50 ) = 1 - P( Z > 1.50 )

= 1 - 0.9332

= 0.0668

The probability is higher than (0.05). Which makes the event unusual, therefore there is no enough evidence which suggest that the number of Americans who are afraid to fly has increased.

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: