If ABC~DEF and the scale factor from ABC to DEF is 3/4, what is the length of DF?

the length of DF = 3/4 AC

see below for explanation

Step-by-step explanation:

ABC is said to be approximately equal to DEF

The scale factor from ABC to DEF = 3/4

From the question, we can tell the original and new shape is a triangle because the lettering to indicate the vertices for both are 3.

We can deduce from the question, ΔABC was dilated to form ΔDEF

In dilation, the length of each of the corresponding side of the new figure is equal to the multiplication of each of the corresponding sides of the old figure and thee scale factor.

In the absence of cordinates for each vertices and length of each sides, ΔABC has 3 sides :

AB, BC and AC

ΔDEF has 3 sides : DE, EF and DF

If AB corresponds to DE

BC corresponds to EF

AC corresponds to DF

Then:

length DE = scale factor × AB = 3/4 AB

length EF = scale factor × BC = 3/4 BC

length DF = scale factor × AC = 3/4 AC

Therefore, the length of DF = 3/4 AC

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !