Which solution can be used to fill in both blanks in the table

(5, 2)

Step-by-step explanation:

As 8x = 40

x = 40÷8

x = 5

This is the first solution

Then 4x + 4y = 28

We know that x = 5 as above

So let's substitute it:

4x + 4y = 28

(4 × 5) + 4y = 28

20 + 4y = 28

Let's get the 20 to other side

20 - 20 + 4y = 28 - 20

4y = 8

y = 8 ÷ 4

y = 2

Hence we get these two solutions

(5,2)

:-)

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west