Find the area enclosed by the graphs of y=√(4-4x), y=√(4-x) and x-axis by integrating with respect to x and integrating with respect to y g

(A) 2/3 [√(4-4x)]^3

(B) 2/3 [√(4-x)]^3

Step-by-step explanation:

Integrating the functions,

(A) Any function in square root is equal to or same as the function raised to the power of 1/2

To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2

Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.

Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.

Here, the denominator is 2, so you take the square root of the function, and raise the function to the power of 3

So the integral of Y = √[4-4x] is

2/3 [√(4-4x)]^3

(B) In like manner, the integral of

Y = √[4-x] is

2/3 [(√4-x)]^3

3 is greater then both of those numbers