A 6-digit number has at least one even digit in its record. How many such numbers are there? (0 is an even digit)

884,375

Step-by-step explanation:

The first digit can't be 0, so there are 9×10⁵ = 900,000 possible six-digit numbers.

Of those, the number of six-digit numbers that have only odd digits is 5⁶ = 15,625.

Numbers with at least one even digit are all numbers that don't have only odd digits.  So the number of six-digit numbers with at least one even digit is:

900,000 − 15,625 = 884,375

answer: 7270

step-by-step explanation: