Find the average rate of change for the function over the given interval. y equals e Superscript x between xequalsnegative 2 and xequals1

Step-by-step explanation:

Given the function y = e^x between the interval x = -2 and x =1, the average rate of change for the function will be the slope of the function expressed as m = Δy/Δx where;

Δy = f(b)-f(a) and Δx = b-a

m =  f(b)-f(a)/b-a where a and b is the interval [-2, 1]

m =  f(1)-f(-2)/1-(-2)

m = f(1)-f(-2)/3

Given the function f(x) = e^x,

at the end point x = b, f(1) = e^1; f(1) = e

at the end point x = a, f(-2) = e^-2; f(-2) = 1/e²

m = (e - 1/e²)/3

m = [(e³ - 1)/e²]/3

m = (e³ - 1)/e² * 1/3

m = (e³ - 1)/3e²

Hence, the average rate of change for the function at the interval [-2, 1] is  (e³ - 1)/3e²

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: