If the quadratic formula is used to solve 2x2-3x - 1 = 0, what are the solutions? 1-3 + fin 3 - i7)
4.
4.
0 -3-17 3 - 171
4
4
이
13 +17 3 - (1)
4
4

x = (3 +/- sqrt(17) / 4.

Step-by-step explanation:

x = [-(-3) +/- sqrt((-3)^2 - 4*2*-1)] / 4

x = (3 +/- sqrt(17) / 4.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0