HELP ASAP PLEASE
I JUST NEED WORK SHOWN BUT ASAP

s = 25.33m

θ = 60.65°

12.37m

A = 160m^2

Step-by-step explanation:

The pyramid has a side base of 35m and a height of 22m.

side base = b = 35m

height of the pyramid = h = 22m

To calculate the slant edge of the pyramid, you first calculate the diagonal of the squared base of the pyramid.

You use the Pythagoras theorem:

With the half of the diagonal and the height, and by using again the Pythagoras theorem you can calculate the slat edge:

The slant edge of the pyramid is 25.33m

The angle of the base is given by:

The angle of the base is 60.65°

The distance between the corner of the pyramid and its center of its base is half of the diagonal, which is 24.74/2 = 12.37m

The area of one side of the pyramid is given by the following formula:

       (1)

l: height of the side of pyramid

then, you first calculate l by using the information about the side base and the slant.

Next, you replace the values of l and b in the equation (1):

The area of one aside of the pyramid is 160m^2