urn I contains 1 red chip and 2 white chips; urn II contains 2 red chipsand 1 white chip. One chip is drawn at random from urn I and transferred to urnII. Then one chip is drawn from urn II. Suppose that a red chip is selected from urnII. What is the probability that the chip transferred was white

Following are the answer to this question:

Step-by-step explanation:

In the question first calls the W if the transmitted chip was white so, the W' transmitted the chip is red or R if the red chip is picked by the urn II.  

whenever a red chip is chosen from urn II, then the probability to transmitters the chip in white is:  

The probability that only the transmitted chip is white is therefore , since urn, I comprise 3 chips and 2 chips are white.

But if the chip is white so, it is possible that urn II has 4 chips and 2 of them will be red since urn II and 2 are now visible, and it is possible to be:

Likewise, the chip transmitted is presumably red and the chip transferred is a red chip of urn II , and a red chip is likely to be red .  

Finally,

The estimation of and as:  

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

its an acute right triangle

step-by-step explanation: