You are graphing Rectangle ABCD in the coordinate plane. The following are three of the vertices of the rectangle A(-7.-2), B(3.–2), and C(3,-5).
What are the coordinates of point D?

  D(-7, -5)

Step-by-step explanation:

There are a couple of ways to figure this.

1) When the rectangle is aligned with the axes, as this one is, each coordinate value shows up twice. In the given list, x-values of 3 are repeated, but -7 is not, so the x-coordinate is -7.

The y-values of -2 are repeated, but -5 is not, so the y-coordinate is -5.

The coordinates of point D are (-7, -5).

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2) The midpoint of diagonal AC is the same as the midpoint of diagonal BD, so the sum of coordinates at the ends of the diagonals will be the same:

  A+C = B+D

Subtracting the coordinates of B from the sum of A and C will give you the coordinates of D:

  D = A +C -B = (-7, -2) +(3, -5) -(3, -2) = (-7+3-3, -2-5+2)

  D = (-7, -5)

Comment on the solution

The second approach works with any parallelogram, rhombus, rectangle, or square--any figure in which the diagonals bisect each other. The figure does not have to be aligned with the axes, as it does in the first approach.

idk lol xd

step-by-step explanation:

ez do it yourself lazy