A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or a 5?

11/21

Step-by-step explanation:

There are 10 even numbers that lie between 1 and 21 (2,4,6,8,10,12,14,16,18, and 20). These 10 balls, plus the 5-ball equals a total of 11 balls that could get picked. Therefore, the probability of picking one of these balls is 11/21.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.